Issue 2051107
Created on 2008-08-14 09:13 by broader, last changed 2016-06-26 22:27 by rouilj.
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msg2579 | Author: [hidden] (broader) | Date: 2008-08-14 09:13 | |
I'm using roundup as backend to construct a GUI program. When call the hyperdb.exportFilename() method,it returns incorrect file path. the old code is : return os.path.join(dirname, self.classname+'-files', subdir_filename) when I change this line to the below: return os.path.join(dirname, 'files',self.classname, subdir_filename) the result is right. So I think that it's maybe a bug? The running environment: OS: Ubuntun 7.10 Python: 2.5.1 roundup: 1.4.4 |
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msg2580 | Author: [hidden] (richard) | Date: 2008-08-18 05:14 | |
Sorry, export works for me. You'll need to be more specific about what sort of error you're getting. |
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msg2581 | Author: [hidden] (broader) | Date: 2008-08-19 14:28 | |
In my ubuntu/linux environment, I has a roundup instance whose directory is : /home/broader/roundup/data and a hyperdb.FileClass instance whose name is 'crecord' is located as below: /home/broader/roundup/data/db/files/crecord When call the hyperdb.exportFilename() method,it returns a incorrect file path as below: /home/broader/roundup/data/db/crecord-files/0/crecordx but the right path should be : /home/broader/roundup/data/db/files/crecord/0/crecordx So, I think its maybe a bug,because in roundup all the hyperdb.FileClass instances will be saved to ../files/(classname)/(0...)/classname(0~...) , not ../classname-files/(0...)/classname(0~...) By the way, I have tested it on Windows environment(XP/python2.5.2/roundup1.4.5.1) also, and got the same result as on Linux/Ubuntu. Best Regards! |
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msg5638 | Author: [hidden] (rouilj) | Date: 2016-06-26 22:27 | |
That function doesn't do what you think it does. To get path to the file in the tracker that sotres file contents use: self.db.filename as below (from hyperdb.py): def export_files(self, dirname, nodeid): """ Export the "content" property as a file, not csv column """ source = self.db.filename(self.classname, nodeid) dest = self.exportFilename(dirname, nodeid) ensureParentsExist(dest) shutil.copyfile(source, dest) exportFilename is used to generate the *target* destination path for the exported directory. What you want is self.db.filename given the class and nodeid. |
History | |||
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Date | User | Action | Args |
2016-06-26 22:27:21 | rouilj | set | status: open -> closed resolution: works for me -> rejected messages: + msg5638 nosy: + rouilj |
2008-08-14 09:13:05 | broader | create |