REVISING HYPOTHESIS THAT THE ERROR MUST BE LOCATED IN THE LAST LINE OF
THE BODY
mach_n(f,n-1)

COMPILER COULD JUST HAVE EXECUTED f

APPROACH:
COMPARE  

def mach_n(f,n):
    if n <= 0:
        return
    else:
        f
        mach_n(f,n-1)

TO ITS MODEL

def print_n(s,n):
    if n <=0:
        return
    print (s)
    print_n(s,n-1)

BY DOWNEY WHICH WORKS. IS THERE A DIFFERENCE WITHIN THE RESPECTIVE CODE?

ANSWER: THERE IS NO else: IN def print_n(s,n):, THE CODE FOR n > 0 IS
INDENTED LIKE else: WOULD HAVE BEEN, EXACTLY BELOW if

-> NEXT STEP:
ERASE else: IN def mach_n(f,n):
INDENT  f
        mach_n(f,n-1)
LIKE print (s)
     print_n(s,n-1)IN def print_n(s,n):